(x^2+2x-3)+(3x^2-2x-8)=

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Solution for (x^2+2x-3)+(3x^2-2x-8)= equation:


Simplifying
(x2 + 2x + -3) + (3x2 + -2x + -8) = 0

Reorder the terms:
(-3 + 2x + x2) + (3x2 + -2x + -8) = 0

Remove parenthesis around (-3 + 2x + x2)
-3 + 2x + x2 + (3x2 + -2x + -8) = 0

Reorder the terms:
-3 + 2x + x2 + (-8 + -2x + 3x2) = 0

Remove parenthesis around (-8 + -2x + 3x2)
-3 + 2x + x2 + -8 + -2x + 3x2 = 0

Reorder the terms:
-3 + -8 + 2x + -2x + x2 + 3x2 = 0

Combine like terms: -3 + -8 = -11
-11 + 2x + -2x + x2 + 3x2 = 0

Combine like terms: 2x + -2x = 0
-11 + 0 + x2 + 3x2 = 0
-11 + x2 + 3x2 = 0

Combine like terms: x2 + 3x2 = 4x2
-11 + 4x2 = 0

Solving
-11 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 4x2 = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 4x2 = 0 + 11
4x2 = 0 + 11

Combine like terms: 0 + 11 = 11
4x2 = 11

Divide each side by '4'.
x2 = 2.75

Simplifying
x2 = 2.75

Take the square root of each side:
x = {-1.658312395, 1.658312395}

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